regex - Split on first/nth occurrence of delimiter -

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I'm trying to get what I thought would be easy. I am looking for a single RJX solution (though others have been welcomed to perfection). I want to divide the n frequencies of a delimiter

Strong> Negative results

says that I want to split the first event of _ : 

  [1] I think I want to split the second event of  _ :   [1] "I like" "to_how_too"   
   
  Solution A regex a liner nth event The solution will use  strsplit  with a single regex.  
 This is a solution that is  strsplit   < Pre>  x <- "I like_to see_how_too" y    
 
 
 Here is another solution using the  gsubfn  package and some regex-fu. To change the  nth  event of the delimiter, you can swap the number that is placed inside the range quantifier ???  {n} .  
  Library (GSUBFN) x & lt; - 'I like_View_Works' Strappe (X, '((?:: [^ _] * _) {1}) (. *)', C, simplify = sub ('_ $', '', x) ) # [1] "I like" "to_how_too"   
 If you want the NIT event  user-defined , then you can use the following:  
  n & lt; - 2 re & lt; --Paste0 ('(': (?: [^ _] * _) {', N,'}) (. *) '' Strepee (X, R, C, simple = sub ('_ $', '', X)) # [1] See "I like_to" "how_to"

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