python - Appending a value to an empty list according to conditions -

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I have a table with many columns. I am interested in only two columns, call them A and B. I want to create an empty column, say c = [] and add it according to some situations. 

  AB11011 12 12 14 14 13 12 12   
 Take the above table as an example.  If the value in column A == 1, then add the value of B to which for A == 1, column C (empty list) appears in column A. until the next A == 1.  The next value of 1 in column A, above.  
 Then I would like to see my column C like this:  
  ABC 1 10 10 11 11 10 0 12 10 1 09 09 0 14 09 0 13 09 1 12 12   
  As you can see, for the first A == 1, B is the value of B in which for A == 1 next A == 1 appears it happens.   
 I was trying something like this, but it is not working:  
  i in: if i == 1: C .append (B [A == i])   
 But lose it through my entire column A and connects several lists  
 I'm about to do it How can i go   
 
 
  a = [1,0,0,1,0,0,1] b = [10,11,12, 9, 14, 13, 12] C = [] temp = B [0] # For the boundary, start a floating variable in the first item (LAN (B)) in B. If A [I] == 1: temp = B [i] # Temporarily update only if 1 was in column C.append (temp) & gt; & Gt; & Gt; C [10, 10, 10, 9, 9, 9, 12]   
  Walk through some iterations for the loop:  < P>  i = 0 ,  a [0]  is  1 ,  becomes temporary   B [ 0]  which is  10  
  i = 1 ,  a [1]  is  0   temporary  resides  B [0]  which is still  10  
  i = 2 ,  a [2]  is  0 ,  is temporary  remains  B [0]  which still is  10  <  I = 3 ,  a [3]  is  1 ,  becomes temporary   B [ 3]  which  9  
 ... is

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