sql - Get an extra row with a join -

-

मान लें कि मेरे पास निम्न तालियां हैं 

  CHAPTERS | आईडी | शीर्षक | --------------------- | 1 | परिचय | LINES | आईडी | अध्याय | लाइन | -------------------------------------- | 2 | 1 | चौदह और ... | | 5 | 1 | शुरुआत में ... |   
 मेरे एसक्यूएल परिणाम में मैं क्या देख रहा हूं  
  | शीर्षक | लाइन | ----------------------------- | परिचय | रिक्त | | परिचय | फोरस्कोर | | परिचय | में भीख मांगना |   
 इसलिए मूल रूप से मैं केवल एक शीर्षक और अन्य पंक्तियों के साथ एक तेज़ी पंक्ति चाहता हूँ मुझे अब जो कुछ मिल गया है, सिर्फ खिताब के बिना लाइन के साथ लाइनों के साथ सिर्फ 2 पंक्तियाँ हैं।  
 कोई विचार?   
 
 
 इसे आज़माएं  
  शीर्षक का चयन करें, अध्यायों से लाइन के रूप में निरर्थक संघ चुनें शीर्षक, अध्यायों से लाइन a.id = B.chapter

Comments

Post a Comment

Popular posts from this blog

java - ImportError: No module named py4j.java_gateway -

-
I'm trying to call the Python using the Java program py4j . I've been installing the plug-in Eclipse and test name Piidvi project. I'm trying to execute the following part of the code found on py4j webpage: Import from py4j.java_gateway to JavaGateway, java_import gateway = JavaGateway () jvm = gateway.jvm java_import (jvm, '' Org.eclipse Kkorkrisorsej. * ") Vrkspes_rut = Jvankresourkesplginkgetvrkspas (). GetRoot (Gateway .help (workspace_root, '* Projects *') project_names = [project.getName () (for projects workpace_root.getProjects))] print (Projekt_nam) But I There is an error in import. I have checked that the P4JJ is present in the Jar Eclipse plugin directory. Can anyone help please? I had to install the py4j application
Read more

python - Receiving "KeyError" after decoding json result from url -

-
I am new to Python I am trying to parse JSON result from a URL. Basically, I was using the following: response = urllib.request.urlopen (url) json_obj = json.load (response) It should be a stroke "str 'not' bytes' in the lines of a given" JSON object, so after searching on the StackoverView Flo, I decode the response in this way: F = urllib.request.urlopen (Url) charset = f.info (). Get_param ('charset', 'utf8') data = f.read () decoded = json.loads (data.decode (charset)) If I print "decode" I is as follows: { 'link': { 'summary data': 'https: // localhost / piwebapi / streams / p0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTExNQU42NDIwXFNJTlVTT0lE / summary' 'value': 'https: // localhost / Piwebapi / streams / P0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTExNQU42NDIwXFNJTlVTT0lE / price ',' InterpolatedData ':' https: // localhost / Piwebapi / streams / P0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTE...
Read more

c# - How to check if a certain method/class/API exists in Xamarin iOS? -

-
After the it is recommended to check for a specific API like this IsiOS7 bool public stable {Returns UIDevice.CurrentDevice.CheckSystemVersion (7, 0); }} If (Util.IsiOS7) {// call iOS 7 API} and {// iOS 6.1 or earlier API call} The same should go for iOS 8. Now I have read that you should check whether there is a certain method or class exists rather than checking the version. Here comes the RespondsToSelector that should be something like this if (RespondsToSelector (new selector ("edgesForExtendedLayout"))) EdgesForExtendedLayout = UIRectEdge.None. But how will one examine if a whole class exists like UIAlertController ? In Objective-C, there is no NSClassFromString I have seen in some such purpose - if ([UIAlertController class]) {// ...} Will such a move happen? type type = type Gettype ("UIAlertController"); If (type! = Null) {// iOS 8 API} other {// iOS 7 or lower} How will this happen in C #? Or to check for UIAlertController...
Read more