Perl regex matches string differently when providing it as variable -

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I got a question about regex matching in Perl. See the following code snippet: 

  My $ r = '^ \ z'; My $ s = ""; $ R = ~ / $ s /? Print "match \ n": print "no match \ n"; Output: Match   
 The following snippet prints:  
  My $ r = '^ \ z'; $ R = ~ / "" /? Print "match \ n": print "no match \ n"; Output: No matching   
 Why? Is this a Perl syntax thing that I do not understand?   
 
 
  my $ s = "";   
 is identical  
  my $ s = '';   
 or  
  my $ s = q ();   
 i.e. It draws  empty string  to  $ s .  
  $ r = ~ / "" /   
 You are checking that there are two double quotes in $ r.  
 To specify a pair of double quotes in $ s,  
  my $ s = '' ';;

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