c++ - delete[] pointer being freed was not allocated -

I am using a new operator to create a dynamic allocated array (I'm using this one because I I want to save on memory above the use of a vector) in the error disaster, saying that the indicator was released, although it was clearly. Constructors and destructors are as follows:

  ~ path () {printf ("path destroyer \ n"); If (points) number {delete}; }} Path (const std :: vector & gt; pathpoint & gt; and digits_) {size = points_.size (); Number = new pathpoint [size]; Int i = 0; (Conf. Pathpoints and P: Points_) {points [i ++] = p; } Printf ("path created \ n"); }    
 
 
 You have to apply:  
 C ++ standard It says that:  
 
 The implicit-fixed copy constructor for a non-union class X copies a member of its subobabs [n 3126 pdf volume 12.8 § 16]  < P> Assignment-Contributed Copy Assignment Operator for a non-union class X assigns the copy of its sub-members to the member's rank. [N3126.pdf Section 12.8 § 30]   
 Then the inherent-defined copy creator and copy assignment operator will not call  new  for your  path  / P>   
  Note:    
    
 < Li> You can also make your type of copy, without the definition of it:   
 Example:  
  Path (const path and other); // Non-creation-copyable path & amp; Operator = (path & amp;); //   
 (or use)  
 
 a  std :: vector & lt; & Gt; Typical overheads of  are very few, there are some references where it really matters: to avoid such problems, use it as much as possible.