math - Python division -

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I was trying to normalize the number from -100 to 0 to 10 to 100 and only problems were To note that there are no variables here, it does not evaluate the way I expect it to be: 

  gt; & Gt; (20-10) / (100-10) 0   
 Float division does not work either:  
  & gt; & Gt; & Gt; If it is inserted on a float on either side of the partition, it will work:  
      & gt; & Gt; & Gt; (20-10) / float ((100-10)) 0.1111111111111111   
 In the first example, each side is evaluating as an int, which means that the final answer will be inserted int . Since 0.111 is less than 5, this is the circumference of 0. This is not transparent in my opinion, but I think that's such a way.  
 What is the explanation?   
 
 
 You are using Python 2.x, where the integer division instead of being a floating point number Will be reduced.  
  & gt; & Gt; & Gt; 1/2 0   
 You get one of them  float :  
  gt; & Gt; & Gt; Float (10 - 20) / (100 - 10) -0.1111111111111111   
 or  __future__ from the import partition , the force  /  To adopt the behavior of 3.x which always gives a float.  
  gt; & Gt; __future__ by Import Split & gt; & Gt; & Gt; (10 - 20) / (100 - 10) -0.1111111111111111

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