terminal - How to keep column headers when using grep? -

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Output of some programs starts with the names of columns (e.g., ps a ): < / P> 

  $ ps a PID TTY STAT time COMMAND 1306 TTY1 SS + 0:00 / sbin / mingetty / dev / TTY1 1318 hvc0 ss + 0:00 / sbin / agetty hvc0 38400 vt100 -Nav 14,696 points / ss0: 00 -bash 15283 points / r + 00:00 ps a   
 Now assume that I have frequencies of  agetty  Want to find:  
  $ ps a | | Grep agetty 1318 hvc0 ss + 0:00 / sbin / agetty hvc0 38400 vt100- nav 15,339 points / s + 00:00 grapes agetty   
 I have seen the beginning of  ps Unless the output of a , I do not know what is the output of  ps? Grep agetty means .  
 I can print the first line after the matching lines:  
  $ ps a | Head-N1; Ps a | Grep agetty pid TTY STAT time COMMAND 1318 hvc0 ss + 0:00 / sbin / agetty hvc0 38400 vt100- nav 15542 points / 0s + 00:00 grep agetty   
 However, This does not solve my problem when I do not know how many header lines are there lines to get a header there and the method did not match the lines, or some less workaround is to achieve this goal?   
 
 
 will this help?  
  ps .. | Awk '/ yourpattern / ||! ^ * S * [0-9] / '  
 Fill in the  yourpattern  in place.  
 You can also  ps ... | Awk '/ agett [y] / || ...  instead of  / agetty /  to filter out the  awk  process itself.

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