awk - compare two columns of two files and give conditional -

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फ़ाइल 1: 

  chr पॉज़ 1 नमूना जीन क्रआर 1 123 नमूना 1 x क्रोए 1 234 नमूना 2 वाई क्रोफ 2 345 नमूना 2 z   
 फ़ाइल 2:  
  नमूना जीन सीआर पॉज़ 1 नमूना 1 एक्स क्रआर 1 123 नमूना 2 एआरआर 1 234 नमूना 2 सीआरआर 3 123 नमूना 2 जेडआरआर 2 345   
 मैंने सामान्य कोड प्राप्त करने के लिए  awk 'NR == FNR {A [$ 1, $ 2] ++; अगला} ए [$ 3, $ 4]' file1 file2  इस्तेमाल किया है, जैसे कि मैंने कोशिश की है  
  awk 'NR == एफएनआर {ए [एफ एन आर] = [$ 1, $ 2] ++; अगला} {प्रिंट एक [$ 3, $ 4] == ए [एफ एन आर] ? $ 0 "\ t" 1: $ 0 "\ t" 0} 'file1 file2   
 लेकिन त्रुटि मिलती है।   
 
]`  
 फास्टस्ट की गई कार्रवाई के रूप में गलत है जिसका उपयोग आपने किया था  एफएनआर  इंडेक्स के रूप में और यहां आप $ 3, $ 4  <प्री>  `ए [एफ एन आर] = [$ 1, $ 2] ++;`   का प्रयोग कर रहे हैं 
 मैंने आपको  ++  का उपयोग समझ नहीं पाया?  
 आपको कुछ पंक्ति का उपयोग करना चाहिए  
  awk 'nr == एफ एन आर { एक [एफ एन आर] = $ 0;} एन.आर. = एफ एन आर {विभाजन (ए [एफ एन आर], लाइन); यदि (रेखा [1] == $ 3 & amp; amp; रेखा [2] == $ 4) प्रिंट $ 0 1; और प्रिंट $ 0 0} 'file1 file2   
 जो आउटपुट को  
  नमूना जीन सीआर पॉस 1 1 नमूना 1 एक्स क्रआर 1 123 1 नमूना 2 ए क्रआर 1 234 1 देगा। Sample2 c chr3 123 0 नमूना 2 z chr2 345 0   
 यहां पहली फ़ाइल के लिए,  NR == FNR  पूरी लाइन को  A < / Code> और दूसरी फ़ाइल के लिए जब  NR! = FNR  सरणी को  split  splited और  $ 3  और  $ 4

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