if statement - How to test in bash one or two conditions -

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I have to check that there is nothing else but a variable: 

  a = "6"; If ["$ a"! = "6"] || ["$ A"! = "4"]; Then echo "OK";  
   
 Returns: OK  
 I just do not get it ...? !!   
 
 
 try  
  if ["$ a"! = "6" -o "$ a"! = "4"] ...   
 But it is not understood that this condition is always true ($ 4 can not be 4 and 6 at the same time). You might want to:  
  instead of  and  if ["$ a"! = "6" -a "$ a"! = "4"] ...

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