regex - selecting all pairs of words in a string in bash -

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How can you select all the pairs of later words in a text in the bash?

For example, for the string test test test 

  test tet test test tezt   
 Should be changed in I have tried to use regular expressions, but it adds half the pairs only after the start of the maitter, where it is omitted, eg  echo "Test Test Test Tzat". Grep -Po '[a-zA-Z] + [a-zA-Z] +'  does not produce only the first and third output, not the second.  
 Please note: the original string is guaranteed to include only spaces and letters  
 EDIT: I need a solution that I will later get pipeline in another program I can do   
 
 
 You can use  awk :  
  s = 'test test test tezt' awk -v RS = '' 'NR & gt; 1 {Print P, $ 1} {p = $ 1} '& lt; & Lt; & Lt; "$ S" Exam Test Test Test Test

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