linux - Set a Bash function on the environment -

I need to define the Bash function in the Bash environment with the C / C ++ program I shellshock Before the bug, I can define a function like this:

  my_func = '() {echo "this is my work";}'   
 or equivalent to C program:  
  setenv ("my_func", "() {echo" This is my work ";)", 1);   
 or  
  putenv ("my_func = () {echo" This is my work ";););   
 But using a Bash version with  shellshock , I can not manage to define my actions in the environment.  
 The strange thing is that if I run  env , then I can define my work in the environment, but if I call it, then Bash says that it does not exist.  
 thanks advance   
 
 
 If you type  bash  Starting with code> execv> > (so that you are only implementing it once), you can (use  execl  for clarification):  
  execl ("/ bin / bash", "Bash", "file_to_run", "arg1", "arg2", 0);   
  
  execl ("/ bin / bash", "bash", "-c", "f () {...} With () {...} \ n. $ 0 "," file_to_run "," arg1 "," arg2 ", 0);   
 And then you do not need to play the game with the internal bad interface to define the function. (If the script is running, then the function is also required to export, for whatever reason, after the code  -c  in the logic,  export -f & lt; func & gt; ;  Add line.)  
 It has the advantage of working with both patch and unread bases.  
 (I have to make patch similar to several programs, so I share your pain.)