vim plugin - Output of programs in vim using SingleCompile -

-

अगर मैं : SCCompileRun को एक फ़ाइल पर 

 <कोड> # शामिल करें & lt; stdio.h & gt; मुख्य () {char s [100]; Printf ("एस \ n" में स्टोर करने के लिए कुछ पाठ दर्ज करें); Scanf ("% s", s); Printf ("\ n% s \ n", s); वापसी ; }   
 मुझे एक आउटपुट जैसा मिलता है:  
  abc को जारी रखने के लिए एंटर दबाएं या कमांड टाइप करें abc में स्टोर करने के लिए कुछ टेक्स्ट दर्ज करें एंटर दबाएं या कमांड को टाइप करें जारी रखें   
 मुझे पूरा कोड चलाने के बाद   में संग्रहीत करने के लिए कुछ पाठ दर्ज करें । क्या यह प्रोग्राम के आउटपुट को प्राप्त करना संभव है क्योंकि इसे कार्यान्वित किया जाता है?   
 
 
 प्रति @ फ़िडीफॉफ, फ्ल्ल्ज (stdout ) काम किया।

Comments

Post a Comment

Popular posts from this blog

java - ImportError: No module named py4j.java_gateway -

-
I'm trying to call the Python using the Java program py4j . I've been installing the plug-in Eclipse and test name Piidvi project. I'm trying to execute the following part of the code found on py4j webpage: Import from py4j.java_gateway to JavaGateway, java_import gateway = JavaGateway () jvm = gateway.jvm java_import (jvm, '' Org.eclipse Kkorkrisorsej. * ") Vrkspes_rut = Jvankresourkesplginkgetvrkspas (). GetRoot (Gateway .help (workspace_root, '* Projects *') project_names = [project.getName () (for projects workpace_root.getProjects))] print (Projekt_nam) But I There is an error in import. I have checked that the P4JJ is present in the Jar Eclipse plugin directory. Can anyone help please? I had to install the py4j application
Read more

python - Receiving "KeyError" after decoding json result from url -

-
I am new to Python I am trying to parse JSON result from a URL. Basically, I was using the following: response = urllib.request.urlopen (url) json_obj = json.load (response) It should be a stroke "str 'not' bytes' in the lines of a given" JSON object, so after searching on the StackoverView Flo, I decode the response in this way: F = urllib.request.urlopen (Url) charset = f.info (). Get_param ('charset', 'utf8') data = f.read () decoded = json.loads (data.decode (charset)) If I print "decode" I is as follows: { 'link': { 'summary data': 'https: // localhost / piwebapi / streams / p0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTExNQU42NDIwXFNJTlVTT0lE / summary' 'value': 'https: // localhost / Piwebapi / streams / P0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTExNQU42NDIwXFNJTlVTT0lE / price ',' InterpolatedData ':' https: // localhost / Piwebapi / streams / P0_7qHaW4UHU-RlCaz8tpasAAQAAAAU0hJTE...
Read more

c# - How to check if a certain method/class/API exists in Xamarin iOS? -

-
After the it is recommended to check for a specific API like this IsiOS7 bool public stable {Returns UIDevice.CurrentDevice.CheckSystemVersion (7, 0); }} If (Util.IsiOS7) {// call iOS 7 API} and {// iOS 6.1 or earlier API call} The same should go for iOS 8. Now I have read that you should check whether there is a certain method or class exists rather than checking the version. Here comes the RespondsToSelector that should be something like this if (RespondsToSelector (new selector ("edgesForExtendedLayout"))) EdgesForExtendedLayout = UIRectEdge.None. But how will one examine if a whole class exists like UIAlertController ? In Objective-C, there is no NSClassFromString I have seen in some such purpose - if ([UIAlertController class]) {// ...} Will such a move happen? type type = type Gettype ("UIAlertController"); If (type! = Null) {// iOS 8 API} other {// iOS 7 or lower} How will this happen in C #? Or to check for UIAlertController...
Read more