c - Sizeof pointer differs from its representation with printf? -

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जब मैं करता हूँ 

  int k = 9; Printf ("sizeof k:% zu \ n", आकारफ (& amp; amp; amp; amp;; k));   
 मुझे आकार  8  के रूप में मिलता है। लेकिन जब मैं  
  प्रिंटफ़ ("p:% p \ n", & amp; amp; k;   
 मुझे  0x7fff57e3ba24  मिलता है। मैं देख सकता हूं कि यह 12 हेक्स नंबर है जिसका अर्थ है (1 हेक्स 4 बीट्स के बाद से) कि सूचक 48 बिट्स पर रखता है जो 6 बाइट्स है।  
 सवाल: क्यों आकार के आकार का प्रिंट 8 सूचक के लिए है, हालांकि इसकी केवल 6 बाइट्स? आपका तर्क यह है कि यदि मैं  
  printf लिखता हूं ("%" डी ", 4);   
 और यह 1 दशमलव अंक प्रिंट करता है, जो संभावित रूप से 1 बाइट में संग्रहीत किया जा सकता है, फिर  sizeof (int)  1 बाइट होना चाहिए।  
 संख्या  0x7fff57e3ba24  समान है  0x00007fff57e3ba24 । सिर्फ इसलिए कि इस प्रकार की संख्या को कम से कम कर सकते हैं, इसका मतलब यह नहीं है कि यह किसी भी कम स्थान पर है।

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