php - Remove one hour from time() -

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I have an online system and after 60 minutes of inactivity one user needs to log out.

The current code is now reduced to 30 minutes. 

  $ cut = time () - 30 * 60;   
 Now I have thought that the following will remove one hour so that time is 60 minutes.  
  $ cut = time () - 60 * 60;   
 This is a complete code that happens. After 60 minutes of inactivity I need a person to log out.  
  // users expire 60 minutes $ final = $ _SESSION ['time']; $ Cut = time () - 60 * 60; If ($ last <$ cut) {session_destroy (); $ Get = $ _GET; $ Location = 'login.php? Timeout = true '; Get foreign currency ($ $ key = & gt; $ item) {$ location. = '& Amp ;;. $ Key "=". $ Item; } Header ('location:'. $ Location); } And $ _SESSION ['time'] = time ();   
 Now that code does not work, I do not think so.   
 
 
 Use strontem () It can be easy  
 Like a session This way, every time the user makes a request, it declares.  
  $ _ session ['time'] = strtotime ("now and");   
 coding part  
  $ last = $ _SESSION ['time']; $ Cut = strotman ("- 60 minutes"); If ($ last & lt; $ cut) // can also use the stratotype ("- 60 minutes") directly {// session_destroy (); Not set ($ _ session ['time']); // Only use the inorder to delete that session = $ _GET; $ Location = 'login.php? Timeout = true '; Get foreign currency ($ $ key = & gt; $ item) {$ location. = '& Amp ;;. $ Key "=". $ Item; } Header ('location:'. $ Location); } And $ _SESSION ['time'] = stratetime ("now");   
  Ensure that the session is started on every page.   
 Works fine ...

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